question_id
int64 0
1.53k
| db_id
stringclasses 11
values | question
stringlengths 23
477
| evidence
stringlengths 0
482
| SQL
stringlengths 29
3.69k
| difficulty
stringclasses 3
values |
|---|---|---|---|---|---|
700
|
codebase_community
|
Identify the number of posts that offer a bounty amount over 30.
|
bounty amount over 30 refers to BountyAmount > = 30;
|
SELECT COUNT(id) FROM votes WHERE BountyAmount >= 30;
|
simple
|
701
|
codebase_community
|
Among all the posts posted by the most influential user, identify the percentage with a score above 50.
|
The most influential user is defined as the user with the highest reputation; the percentage is calculated based on the proportion of posts with a score above 50 among all posts by that user;
|
SELECT CAST(SUM(CASE WHEN T2.Score > 50 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T1.Id) FROM users T1 INNER JOIN posts T2 ON T1.Id = T2.OwnerUserId INNER JOIN ( SELECT MAX(Reputation) AS max_reputation FROM users ) T3 ON T1.Reputation = T3.max_reputation
|
challenging
|
702
|
codebase_community
|
How many posts have a score less than 20?
|
score less than 20 refers to Score < 20;
|
SELECT COUNT(id) FROM posts WHERE Score < 20
|
simple
|
703
|
codebase_community
|
Among the tags with tag ID below 15, how many of them have 20 count of posts and below?
|
ID below 15 refers to Id < 15; have 20 count of posts and below refers to Count < = 20;
|
SELECT COUNT(id) FROM tags WHERE Count <= 20 AND Id < 15
|
simple
|
704
|
codebase_community
|
What is the excerpt post ID and wiki post ID of the tag named sample?
|
tag named sample refers to TagName = 'sample';
|
SELECT ExcerptPostId, WikiPostId FROM tags WHERE TagName = 'sample'
|
simple
|
705
|
codebase_community
|
Give the user's reputation and up vote number of the user that commented "fine, you win :)".
|
Text = 'fine, you win :)'
|
SELECT T2.Reputation, T2.UpVotes FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Text = 'fine, you win :)'
|
simple
|
706
|
codebase_community
|
Give the texts commented on the post about linear regression.
|
about linear regression refers to Title contains 'linear regression'
|
SELECT T1.Text FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.Title LIKE '%linear regression%'
|
simple
|
707
|
codebase_community
|
Among the posts with views ranging from 100 to 150, what is the comment with the highest score?
|
comment with the highest score refers to Text where MAX(Score);
|
SELECT Text FROM comments WHERE PostId IN ( SELECT Id FROM posts WHERE ViewCount BETWEEN 100 AND 150 ) ORDER BY Score DESC LIMIT 1
|
moderate
|
708
|
codebase_community
|
List the creation date and age of the user that commented with webiste.
|
commented with webiste refers to the value contains 'http://'
|
SELECT T2.CreationDate, T2.Age FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.text LIKE '%http://%'
|
moderate
|
709
|
codebase_community
|
In comments with 0 score, how many of the posts have view count lower than 5?
|
view count lower than 5 refers to ViewCount < 5;
|
SELECT COUNT(DISTINCT T2.Id) FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.ViewCount < 5 AND T1.Score = 0
|
simple
|
710
|
codebase_community
|
In posts with 1 comment, how many of the comments have 0 score?
|
in posts with 1 comment refers to CommentCount = 1;
|
SELECT COUNT(T1.id)
FROM comments AS T1
INNER JOIN posts AS T2 ON T1.PostId = T2.Id
WHERE T2.CommentCount = 1 AND T1.Score = 0;
|
simple
|
711
|
codebase_community
|
Among product comments with 0 score, what is the total number of users aged 40 years old?
|
SELECT COUNT(DISTINCT T2.Id)
FROM comments AS T1
INNER JOIN users AS T2 ON T1.UserId = T2.Id
WHERE T1.Score = 0 AND T2.Age = 40;
|
simple
|
|
712
|
codebase_community
|
What is the post ID and the comments commented in the post titled by "Group differences on a five point Likert item"?
|
Title = 'Group differences on a five point Likert item';
|
SELECT T2.Id, T1.Text FROM comments AS T1 INNER JOIN posts AS T2 ON T1.PostId = T2.Id WHERE T2.Title = 'Group differences on a five point Likert item'
|
simple
|
713
|
codebase_community
|
What is the up vote number of the user that commented "R is also lazy evaluated."?
|
commented "R is also lazy evaluated." refers to Text of the comment;
|
SELECT T2.UpVotes FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Text = 'R is also lazy evaluated.'
|
simple
|
714
|
codebase_community
|
List the comments commented by the user with a username of Harvey Motulsky.
|
comments refer to Text; username of Harvey Motulsky refers to DisplayName = 'Harvey Motulsky';
|
SELECT T1.Text FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T2.DisplayName = 'Harvey Motulsky'
|
simple
|
715
|
codebase_community
|
In comments with score between 1 to 5, list down the display names of the users with 0 down votes.
|
DownVotes = 0; Score BETWEEN 1 and 5
|
SELECT DISTINCT T2.DisplayName FROM comments AS T1 INNER JOIN users AS T2 ON T1.UserId = T2.Id WHERE T1.Score BETWEEN 1 AND 5 AND T2.DownVotes = 0
|
simple
|
716
|
codebase_community
|
Among the comments with scores between 5 to 10, what is the percentage of the users with 0 up votes?
|
percentage = DIVIDE(COUNT(UserId where UpVotes = 0 and Score BETWEEN 5 and 10))*100, (COUNT(UserId where Score BETWEEN 5 and 10));
|
SELECT CAST(COUNT(DISTINCT CASE WHEN T1.UpVotes = 0 THEN T1.Id END) AS REAL) * 100/ COUNT(DISTINCT T1.Id) AS per FROM users AS T1 INNER JOIN comments AS T2 ON T1.Id = T2.UserId WHERE T2.Score BETWEEN 5 AND 10
|
moderate
|
717
|
superhero
|
Please list all the superpowers of 3-D Man.
|
3-D Man refers to superhero_name = '3-D Man'; superpowers refers to power_name
|
SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = '3-D Man'
|
simple
|
718
|
superhero
|
How many superheroes have the super power of "Super Strength"?
|
super power of "Super Strength" refers to power_name = 'Super Strength'
|
SELECT COUNT(T1.hero_id) FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Super Strength'
|
simple
|
719
|
superhero
|
Among the superheroes with the super power of "Super Strength", how many of them have a height of over 200cm?
|
'Super Strength' refers to power_name
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Super Strength' AND T1.height_cm > 200
|
moderate
|
720
|
superhero
|
Please list the full names of all the superheroes with over 15 super powers.
|
15 super powers refers to COUNT(full_name) > 15
|
SELECT DISTINCT T1.full_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id GROUP BY T1.full_name HAVING COUNT(T2.power_id) > 15
|
simple
|
721
|
superhero
|
How many superheroes have blue eyes?
|
blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id;
|
SELECT COUNT(T1.id)
FROM superhero AS T1
INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id
WHERE T2.colour = 'Blue';
|
simple
|
722
|
superhero
|
What is the colour of Apocalypse's skin?
|
Apocalypse refers to superhero_name = 'Apocalypse'; colour of skin refers to colour where skin_colour_id = colour.id
|
SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.skin_colour_id = T2.id WHERE T1.superhero_name = 'Apocalypse'
|
simple
|
723
|
superhero
|
Among the superheroes with blue eyes, how many of them have the super power of "Agility"?
|
blue eyes refers to the eye colour = 'Blue' in the colour table; super power of "Agility" refers to power_name = 'Agility'
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id INNER JOIN colour AS T4 ON T1.eye_colour_id = T4.id WHERE T3.power_name = 'Agility' AND T4.colour = 'Blue'
|
moderate
|
724
|
superhero
|
Please list the superhero names of all the superheroes that have blue eyes and blond hair.
|
blue eyes refers to colour = 'Blue' and eye_colour_id = colour.id; blond hair refers to colour = 'Blond' and hair_colour_id = colour.id;
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Blond'
|
challenging
|
725
|
superhero
|
How many superheroes are published by Marvel Comics?
|
published by Marvel Comics refers to publisher_name = 'Marvel Comics'
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Marvel Comics'
|
simple
|
726
|
superhero
|
Rank heroes published by Marvel Comics by their height in descending order.
|
published by Marvel Comics refers to publisher_name = 'Marvel Comics'
|
SELECT superhero_name, height_cm, RANK() OVER (ORDER BY height_cm DESC) AS HeightRank FROM superhero INNER JOIN publisher ON superhero.publisher_id = publisher.id WHERE publisher.publisher_name = 'Marvel Comics'
|
moderate
|
727
|
superhero
|
Who is the publisher of Sauron?
|
the publisher refers to publisher_name; Sauron refers to superhero_name = 'Sauron'
|
SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name = 'Sauron'
|
simple
|
728
|
superhero
|
Rank superheroes from Marvel Comics by their eye color popularity, starting with the most common color.
|
the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; most common color refers to COUNT(superhero.id) DESC;
|
SELECT colour.colour AS EyeColor, COUNT(superhero.id) AS Count, RANK() OVER (ORDER BY COUNT(superhero.id) DESC) AS PopularityRank FROM superhero INNER JOIN colour ON superhero.eye_colour_id = colour.id INNER JOIN publisher ON superhero.publisher_id = publisher.id WHERE publisher.publisher_name = 'Marvel Comics' GROUP BY colour.colour
|
moderate
|
729
|
superhero
|
What is the average height of the superheroes from Marvel Comics?
|
superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; average height of the superheroes refers to AVG(height_cm)
|
SELECT AVG(T1.height_cm) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Marvel Comics'
|
simple
|
730
|
superhero
|
List the superheroes from Marvel Comics who have the super power of 'Super Strength'.
|
the superheroes from Marvel Comics refers to publisher_name = 'Marvel Comics'; super power of "Super Strength" refers to power_name = 'Super Strength';
|
SELECT superhero_name FROM superhero AS T1 WHERE EXISTS (SELECT 1 FROM hero_power AS T2 INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Super Strength' AND T1.id = T2.hero_id)AND EXISTS (SELECT 1 FROM publisher AS T4 WHERE T4.publisher_name = 'Marvel Comics' AND T1.publisher_id = T4.id)
|
challenging
|
731
|
superhero
|
How many superheroes did DC Comics publish?
|
superheroes that DC Comics published refers to publisher_name = 'DC Comics'
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'DC Comics'
|
simple
|
732
|
superhero
|
Which publisher published the slowest superhero?
|
the slowest superhero refers to attribute_name = 'Speed' where MIN(attribute_value); publisher refers to publisher_name
|
SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN hero_attribute AS T3 ON T1.id = T3.hero_id INNER JOIN attribute AS T4 ON T3.attribute_id = T4.id WHERE T4.attribute_name = 'Speed' ORDER BY T3.attribute_value LIMIT 1
|
moderate
|
733
|
superhero
|
How many gold-eyed superheroes did Marvel Comics publish?
|
gold-eyed refers to colour = 'Gold' where eye_colour_id = colour.id; superheroes that Marvel Comics published refers to publisher_name = 'Marvel Comics'
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN colour AS T3 ON T1.eye_colour_id = T3.id WHERE T2.publisher_name = 'Marvel Comics' AND T3.colour = 'Gold'
|
moderate
|
734
|
superhero
|
What is the publisher's name of Blue Beetle II?
|
SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name = 'Blue Beetle II'
|
simple
|
|
735
|
superhero
|
How many superheroes with blonde hair are there?
|
superheroes with blonde hair refers to colour = 'Blond' where hair_colour_id = colour.id
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.hair_colour_id = T2.id WHERE T2.colour = 'Blond'
|
simple
|
736
|
superhero
|
Who is the dumbest superhero?
|
The dumbest superhero is the one with the lowest intelligence attribute value.
|
SELECT T1.superhero_name
FROM superhero AS T1
INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id
INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id
WHERE T3.attribute_name = 'Intelligence'
ORDER BY T2.attribute_value ASC, T1.id ASC
LIMIT 1
|
moderate
|
737
|
superhero
|
What is Copycat's race?
|
Copycat is the superhero_name;
|
SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.superhero_name = 'Copycat'
|
simple
|
738
|
superhero
|
Which superheroes have a durability attribute value of less than 50?
|
durability of less than 50 refers to attribute_name = 'Durability' AND attribute_value < 50
|
SELECT superhero_name FROM superhero AS T1 WHERE EXISTS (SELECT 1 FROM hero_attribute AS T2 INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Durability' AND T2.attribute_value < 50 AND T1.id = T2.hero_id)
|
simple
|
739
|
superhero
|
What are the names of the superheroes with the power of death touch?
|
name of superheroes refers to refers to superhero_name; the power of death touch refers to power_name = 'Death Touch'
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Death Touch'
|
moderate
|
740
|
superhero
|
How many female superheroes have a strength value of 100?
|
female refers to gender = 'Female'; strength value of 100 refers to attribute_name = 'Strength' AND attribute_value = 100
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id INNER JOIN gender AS T4 ON T1.gender_id = T4.id WHERE T3.attribute_name = 'Strength' AND T2.attribute_value = 100 AND T4.gender = 'Female'
|
moderate
|
741
|
superhero
|
What is the name of the superhero that has the most powers?
|
name of the superhero refers to superhero_name; superhero that has the most powers refers to MAX(COUNT(superhero_name))
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id GROUP BY T1.superhero_name ORDER BY COUNT(T2.hero_id) DESC LIMIT 1
|
simple
|
742
|
superhero
|
How many vampire superheroes are there?
|
vampire superheroes refers to race = 'Vampire'
|
SELECT COUNT(T1.superhero_name) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Vampire'
|
simple
|
743
|
superhero
|
What is the percentage of superheroes who act in their own self-interest or make decisions based on their own moral code? Indicate how many of the said superheroes were published by Marvel Comics.
|
published by Marvel Comics refers to publisher_name = 'Marvel Comics'; superheroes who act in their own self-interest or make decisions based on their own moral code refers to alignment = 'Bad'; calculation = MULTIPLY(DIVIDE(SUM(alignment = 'Bad); count(id)), 100)
|
SELECT (CAST(COUNT(*) AS REAL) * 100 / (SELECT COUNT(*) FROM superhero)), CAST(SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) AS REAL) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN alignment AS T3 ON T3.id = T1.alignment_id WHERE T3.alignment = 'Bad'
|
challenging
|
744
|
superhero
|
Between DC and Marvel Comics, which publisher has published more superheroes? Find the difference in the number of superheroes they have published.
|
DC refers to publisher_name = 'DC Comics'; Marvel Comics refers to publisher_name = 'Marvel Comics'; calculation = SUBTRACT(SUM(publisher_name = 'Marvel Comics'), SUM(publisher_name = 'DC Comics'))
|
SELECT SUM(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE 0 END) - SUM(CASE WHEN T2.publisher_name = 'DC Comics' THEN 1 ELSE 0 END) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id
|
challenging
|
745
|
superhero
|
Give the publisher ID of Star Trek.
|
SELECT id FROM publisher WHERE publisher_name = 'Star Trek'
|
simple
|
|
746
|
superhero
|
Calculate the average attribute value of all superheroes.
|
average attribute value of all superheroes refers to AVG(attribute_value)
|
SELECT AVG(attribute_value) FROM hero_attribute
|
simple
|
747
|
superhero
|
What is the total number of superheroes without full name?
|
superheroes without full name refers to full_name IS NULL
|
SELECT COUNT(id) FROM superhero WHERE full_name IS NULL
|
simple
|
748
|
superhero
|
What is the eye colour of superhero with superhero ID 75?
|
eye colour refers to colour where eye_colour_id = colour.id;
|
SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.id = 75
|
simple
|
749
|
superhero
|
Provide the superpowers of the superhero called Deathlok.
|
superpowers refers to power_name; Deathlok refers to superhero_name = 'Deathlok'
|
SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Deathlok'
|
simple
|
750
|
superhero
|
What is the average weight of all female superheroes?
|
female refers to gender = 'Female'; average weight refers to AVG(weight_kg)
|
SELECT AVG(T1.weight_kg) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Female'
|
simple
|
751
|
superhero
|
List down at least five superpowers of male superheroes.
|
male refers to gender = 'Male'; superpowers refers to power_name;
|
SELECT T3.power_name
FROM superhero AS T1
INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id
INNER JOIN superpower AS T3 ON T3.id = T2.power_id
INNER JOIN gender AS T4 ON T4.id = T1.gender_id
WHERE T4.gender = 'Male'
LIMIT 5;
|
moderate
|
752
|
superhero
|
Give the name of the alien superheroes.
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Alien'
|
simple
|
|
753
|
superhero
|
Among the superheroes with height from 170 to 190, list the names of the superheroes with no eye color.
|
height from 170 to 190 refers to height in centimeters between 170 and 190; no eye color is labeled as 'No Colour' in the database
|
SELECT DISTINCT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.height_cm BETWEEN 170 AND 190 AND T2.colour = 'No Colour'
|
moderate
|
754
|
superhero
|
What is the superpower of hero ID 56?
|
SELECT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T1.hero_id = 56
|
simple
|
|
755
|
superhero
|
List down at least five full name of Demi-God superheroes.
|
Demi-God superheroes refers to race = 'Demi-God'
|
SELECT T1.full_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Demi-God'
|
simple
|
756
|
superhero
|
How many bad superheroes are there?
|
bad superheroes refers to alignment_id = Bad
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Bad'
|
simple
|
757
|
superhero
|
Identify the race of the superhero who weighed 169 kg.
|
SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.weight_kg = 169
|
simple
|
|
758
|
superhero
|
Provide the hair colour of the human superhero who is 185 cm tall.
|
185 cm tall refers to height_cm = 185; human superhero refers to race = 'human'; hair colour refers to colour where hair_colour_id = colour.id;
|
SELECT DISTINCT T3.colour FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T1.height_cm = 185 AND T2.race = 'Human'
|
moderate
|
759
|
superhero
|
What is the eye clolour of the heaviest superhero?
|
the heaviest superhero refers to MAX(weight_kg); eye colour refers to colour where eye_colour_id = colour.id;
|
SELECT T2.colour
FROM superhero AS T1
INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id
ORDER BY T1.weight_kg DESC
LIMIT 1;
|
simple
|
760
|
superhero
|
In superheroes with height between 150 to 180, what is the percentage of heroes published by Marvel Comics?
|
heroes published by Marvel Comics refers to publisher_name = 'Marvel Comics'; percentage is calculated as (Marvel Comics heroes / total heroes) * 100
|
SELECT CAST(COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.height_cm BETWEEN 150 AND 180
|
challenging
|
761
|
superhero
|
Among the male superheroes, list the super hero names of superheroes with weight greater than the 79% average weight of all superheroes.
|
super hero names refers to superhero_name;male superheros refers to gender = 'Male';Calculation = weight_kg > MULTIPLY(AVG(weight_kg), 0.79)
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T2.gender = 'Male' AND T1.weight_kg * 100 > ( SELECT AVG(weight_kg) FROM superhero ) * 79
|
moderate
|
762
|
superhero
|
Which power do superheroes have the most of?
|
power that superheroes have the most refers to MAX(COUNT(power_name))
|
SELECT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id GROUP BY T2.power_name ORDER BY COUNT(T1.hero_id) DESC LIMIT 1
|
simple
|
763
|
superhero
|
Indicate the attribute value of superhero Abomination.
|
Abomination refers to superhero_name = 'Abomination';
|
SELECT a.attribute_name AS hero_attribute_name, ha.attribute_value AS hero_attribute_value FROM superhero s INNER JOIN hero_attribute ha ON s.id = ha.hero_id INNER JOIN attribute a ON ha.attribute_id = a.id WHERE s.superhero_name = 'Abomination';
|
simple
|
764
|
superhero
|
What are the superpowers of heroes with ID 1?
|
SELECT DISTINCT T2.power_name FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T1.hero_id = 1
|
simple
|
|
765
|
superhero
|
How many heroes have stealth power?
|
SELECT COUNT(T1.hero_id) FROM hero_power AS T1 INNER JOIN superpower AS T2 ON T1.power_id = T2.id WHERE T2.power_name = 'Stealth'
|
simple
|
|
766
|
superhero
|
What is the hero's full name with the highest attribute in strength?
|
highest attribute in strength refers to MAX(attribute_value) WHERE attribute_name = 'strength';
|
SELECT T1.full_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Strength' ORDER BY T2.attribute_value DESC LIMIT 1
|
moderate
|
767
|
superhero
|
What is the proportion of superheroes with no skin colour?
|
no skin colour refers to skin_colour_id = 1 where colour is 'No Colour'; proportion is calculated as the number of superheroes with no skin colour divided by the total number of superheroes.
|
SELECT CAST(SUM(CASE WHEN skin_colour_id = 1 THEN 1 ELSE 0 END) AS REAL) / COUNT(*) FROM superhero
|
simple
|
768
|
superhero
|
How many superheroes were published by Dark Horse Comics?
|
[Remove Evidence]
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.publisher_name = 'Dark Horse Comics'
|
simple
|
769
|
superhero
|
Which superhero has the most durability published by Dark Horse Comics?
|
most durability refers to MAX(attribute_value) WHERE attribute_name = 'Durability'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics'
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T3.id = T2.attribute_id INNER JOIN publisher AS T4 ON T4.id = T1.publisher_id WHERE T4.publisher_name = 'Dark Horse Comics' AND T3.attribute_name = 'Durability' ORDER BY T2.attribute_value DESC, T1.superhero_name ASC LIMIT 1
|
challenging
|
770
|
superhero
|
What is the eyes colour of Abraham Sapien?
|
eye colour refers to colour.colour where eye_colour_id = colour.id; Abraham Sapien is the full name of superhero;
|
SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T1.full_name = 'Abraham Sapien'
|
simple
|
771
|
superhero
|
List the name of superheroes with flight power.
|
name of superheroes refers to superhero_name; flight power refers to power_name = 'Flight';
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Flight'
|
simple
|
772
|
superhero
|
List the eyes, hair and skin colour of all female superheroes published by Dark Horse Comics.
|
eyes refers to eye_colour_id; hair refers to hair_colour_id; skin colour refers to skin_colour_id; female superheroes refers to gender = 'Female'; published by Dark Horse Comics refers to publisher_name = 'Dark Horse Comics';
|
SELECT T1.eye_colour_id, T1.hair_colour_id, T1.skin_colour_id FROM superhero AS T1 INNER JOIN publisher AS T2 ON T2.id = T1.publisher_id INNER JOIN gender AS T3 ON T3.id = T1.gender_id WHERE T2.publisher_name = 'Dark Horse Comics' AND T3.gender = 'Female'
|
challenging
|
773
|
superhero
|
Which superhero has the same eyes, hair and skin colour? Indicate the publisher of the superhero.
|
which superhero refers to superhero_name; the same eyes, hair and skin colour refers to hair_colour_id = skin_colour_id AND hair_colour_id = eye_colour_id; publisher refers to publisher_name;
|
SELECT T1.superhero_name, T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.eye_colour_id = T1.hair_colour_id AND T1.eye_colour_id = T1.skin_colour_id
|
challenging
|
774
|
superhero
|
Which group does superhero A-Bomb belong to?
|
group refers to race; A-Bomb refers to superhero_name = 'A-Bomb';
|
SELECT T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.superhero_name = 'A-Bomb'
|
simple
|
775
|
superhero
|
What is the percentage of blue female superheroes among all female superheroes?
|
blue refers to skin color and represented as 'Blue' in the data; female is represented as 'Female' in the data;
|
SELECT CAST(COUNT(CASE WHEN T3.colour = 'Blue' THEN T1.id ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T2.gender = 'Female'
|
challenging
|
776
|
superhero
|
Provide the hero name and race of Charles Chandler.
|
hero name refers to superhero_name; Charles Chandler is the full name of superhero;
|
SELECT T1.superhero_name, T2.race FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T1.full_name = 'Charles Chandler'
|
simple
|
777
|
superhero
|
What is the gender of Agent 13 hero?
|
Agent 13 hero refers to superhero_name = 'Agent 13';
|
SELECT T2.gender FROM superhero AS T1 INNER JOIN gender AS T2 ON T1.gender_id = T2.id WHERE T1.superhero_name = 'Agent 13'
|
simple
|
778
|
superhero
|
Provide superheroes' names who have the adaptation power.
|
adaptation power refers to power_name = 'Adaptation';
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T3.power_name = 'Adaptation'
|
simple
|
779
|
superhero
|
How many powers does Amazo hero have?
|
Amazo hero refers to superhero_name = 'Amazo';
|
SELECT COUNT(T1.power_id) FROM hero_power AS T1 INNER JOIN superhero AS T2 ON T1.hero_id = T2.id WHERE T2.superhero_name = 'Amazo'
|
simple
|
780
|
superhero
|
List the powers of Hunter Zolomon.
|
Hunter Zolomon is the full name of superhero; list the powers refers to power_name;
|
SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.full_name = 'Hunter Zolomon'
|
simple
|
781
|
superhero
|
Provide the heights of the heroes whose eye colours are amber.
|
SELECT T1.height_cm FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id WHERE T2.colour = 'Amber'
|
simple
|
|
782
|
superhero
|
List the heroes' names whose eyes and hair colours are both black.
|
heroes' names refers to superhero_name; eyes and hair colours are both black refer to eye_colour_id and hair_colour_id are both black;
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id AND T1.hair_colour_id = T2.id WHERE T2.colour = 'Black'
|
moderate
|
783
|
superhero
|
Provide the eye colours of the heroes whose skin colours are gold.
|
skin colours are gold refers to colour.colour = 'Gold' WHERE skin_colour_id = colour.id;
|
SELECT T2.colour FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.skin_colour_id = T3.id WHERE T3.colour = 'Gold'
|
simple
|
784
|
superhero
|
Provide the full names of vampire heroes.
|
vampire heroes refers to race = 'Vampire';
|
SELECT T1.full_name FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Vampire'
|
simple
|
785
|
superhero
|
Describe the names of neutral alignment superheroes.
|
names of superheroes refers to superhero_name; neutral alignment refers to alignment = 'Neutral';
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral'
|
simple
|
786
|
superhero
|
How many heroes have the highest attribute value in strength?
|
highest attribute value in strength refers to MAX(attribute_value) WHERE attribute_name = 'Strength';
|
SELECT COUNT(T1.hero_id) FROM hero_attribute AS T1 INNER JOIN attribute AS T2 ON T1.attribute_id = T2.id WHERE T2.attribute_name = 'Strength' AND T1.attribute_value = ( SELECT MAX(attribute_value) FROM hero_attribute )
|
moderate
|
787
|
superhero
|
What are the race and alignment of Cameron Hicks?
|
Cameron Hicks refers to superhero_name = 'Cameron Hicks';
|
SELECT T2.race, T3.alignment FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN alignment AS T3 ON T1.alignment_id = T3.id WHERE T1.superhero_name = 'Cameron Hicks'
|
simple
|
788
|
superhero
|
How many percent of female heroes were published by Marvel Comics?
|
percent = MULTIPLY(DIVIDE(SUM(gender = 'Female' WHERE publisher_name = 'Marvel Comics'), COUNT(publisher_name = 'Marvel Comics')), 100); female heroes refers to gender = 'Female'; Marvel Comics refers to publisher_name = 'Marvel Comics';
|
SELECT CAST(COUNT(CASE WHEN T2.publisher_name = 'Marvel Comics' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id INNER JOIN gender AS T3 ON T1.gender_id = T3.id WHERE T3.gender = 'Female'
|
challenging
|
789
|
superhero
|
Find the average weight of the heroes who are aliens.
|
average = AVG(weight_kg); aliens refers to race = 'Alien';
|
SELECT CAST(SUM(T1.weight_kg) AS REAL) / COUNT(T1.id) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id WHERE T2.race = 'Alien'
|
simple
|
790
|
superhero
|
Calculate the difference between Emil Blonsky's weight and Charles Chandler's weight.
|
Emil Blonsky and Charles Chandler are the full names of superheros;
|
SELECT ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Emil Blonsky' ) - ( SELECT weight_kg FROM superhero WHERE full_name LIKE 'Charles Chandler' ) AS CALCULATE
|
moderate
|
791
|
superhero
|
Calculate the average height for each superhero.
|
average = DIVIDE(SUM(height_cm), COUNT(all heros));
|
SELECT CAST(SUM(height_cm) AS REAL) / COUNT(id) FROM superhero
|
simple
|
792
|
superhero
|
What is Abomination's superpower?
|
Abomination refers to superhero_name = 'Abomination'; superpower refers to power_name;
|
SELECT T3.power_name FROM superhero AS T1 INNER JOIN hero_power AS T2 ON T1.id = T2.hero_id INNER JOIN superpower AS T3 ON T2.power_id = T3.id WHERE T1.superhero_name = 'Abomination'
|
simple
|
793
|
superhero
|
Among the superheroes with the race of god/eternal, how many of them are male
|
race "god/eternal" refers to race_id = 21; male refers to gender.id = 1
|
SELECT COUNT(*) FROM superhero AS T1 INNER JOIN race AS T2 ON T1.race_id = T2.id INNER JOIN gender AS T3 ON T3.id = T1.gender_id WHERE T1.race_id = 21 AND T1.gender_id = 1
|
simple
|
794
|
superhero
|
Which hero was the fastest?
|
The fastest hero is the one with the highest speed value.
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T3.attribute_name = 'Speed' ORDER BY T2.attribute_value DESC, T1.id ASC LIMIT 1
|
moderate
|
795
|
superhero
|
How many superheroes have a neutral alignment?
|
neutral alignment refers to alignment_id = 3;
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN alignment AS T2 ON T1.alignment_id = T2.id WHERE T2.alignment = 'Neutral'
|
simple
|
796
|
superhero
|
State all of 3-D Man's attributes along with their values.
|
3-D Man is the superhero_name. attributes refers to attribute_name; values refers to attribute_value;
|
SELECT T3.attribute_name, T2.attribute_value FROM superhero AS T1 INNER JOIN hero_attribute AS T2 ON T1.id = T2.hero_id INNER JOIN attribute AS T3 ON T2.attribute_id = T3.id WHERE T1.superhero_name = '3-D Man'
|
moderate
|
797
|
superhero
|
Which superheroes have blue eyes with brown hair?
|
blue eyes refers to eye_colour_id; brown hair refers to hair_colour_id; both colors are stored in the colour table
|
SELECT T1.superhero_name FROM superhero AS T1 INNER JOIN colour AS T2 ON T1.eye_colour_id = T2.id INNER JOIN colour AS T3 ON T1.hair_colour_id = T3.id WHERE T2.colour = 'Blue' AND T3.colour = 'Brown'
|
moderate
|
798
|
superhero
|
What is the publisher for Hawkman, Karate Kid and Speedy?
|
publisher refers to publisher_name; Hawkman refers to superhero_name = 'Hawkman'; Karate Kid refers to superhero_name = 'Karate Kid'; Speedy refers to superhero_name = 'Speedy';
|
SELECT T2.publisher_name FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T1.superhero_name IN ('Hawkman', 'Karate Kid', 'Speedy')
|
moderate
|
799
|
superhero
|
How many superheroes didn't have any publisher?
|
didn't have any publisher refers to publisher.id = 1;
|
SELECT COUNT(T1.id) FROM superhero AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.id WHERE T2.id = 1
|
simple
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.